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Text: >>> for x in ['{0:3n} 0b{0:08b} {1}'.format(x, ('X' if (x & 0b00001000) and (x & 0b00000100) else '')) for x in range(0,40)]: print(x) ... 0 0b00000000 1 0b00000001 2 0b00000010 3 0b00000011 4 0b00000100 5 0b00000101 6 0b00000110 7 0b00000111 8 0b00001000 9 0b00001001 10 0b00001010 11 0b00001011 12 0b00001100 X 13 0b00001101 X 14 0b00001110 X 15 0b00001111 X 16 0b00010000 17 0b00010001 18 0b00010010 19 0b00010011 20 0b00010100 21 0b00010101 22 0b00010110 23 0b00010111 24 0b00011000 25 0b00011001 26 0b00011010 27 0b00011011 28 0b00011100 X 29 0b00011101 X 30 0b00011110 X 31 0b00011111 X 32 0b00100000 33 0b00100001 34 0b00100010 35 0b00100011 36 0b00100100 37 0b00100101 38 0b00100110 39 0b00100111